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1-2x+(13/4)x^2=0
Domain of the equation: 4)x^2!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-2x+(+13/4)x^2+1=0
We multiply all the terms by the denominator
-2x*4)x^2+(+1*4)x^2+13=0
We add all the numbers together, and all the variables
-2x*4)x^2+4x^2+13=0
Wy multiply elements
-8x^2=0
a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-16}=0$
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